Question

Find the value of 9 cot square theta + 9 if sin theta=1 divided 3

Answer 1

ans : 89/9

Explanation:

let theta be x

9cot^2x+9

given sinx:1/3

we have

• cotx :cosx/sinx
• then cot^2x:cos^2x/sin^2x
• and cos^2x+sin^2x:1

NOW

• 9Cos^2x/sin^2x+9
• 9cos^2x/(1/3)^2+9
• 9cos^2x/(1/9)+9
• 9cos^2x.1/9+9
• 9/9.cos^2x+9
• 1.cos^2x+9
• cos^2x+9

cos^2x : ?

from above

we have

cos^2x+sin^2x : 1

cos^2x+(1/3)^2 : 1

cos^2x+(1/9):1

cos^2x : 1-(1/9)

cos^2x : 9-1/9

cos^2x : 8/9

now we got

cos^2x : 8/9

finally

8/9+9

8+9(9)/9

8+81/9

89/9

✓9cot^2x+9 : 89/9