Math, asked by dhanushs193, 9 months ago

find the value of 9 sec^2 A + 9 tan^2 A

Answers

Answered by rajivrtp

0

Answer:

9(2tan²A+1)

Step-by-step explanation:

9sec²A+9tan²A

= 9( 1+tan²A+tan²A)

= 9( 2tan²A+1)

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