Find the value of (9 sec)2A _(tan)2A
Answers
Answered by
1
Answer:
We have, 9sec
2
A−9tan
2
A
Let r=9sec
2
A−9tan
2
A
r=9(sec
2
A−tan
2
A)
We know that
sec
2
A−tan
2
A=1
Therefore,
r=9×1=9
Hence, this is the answer.
Step-by-step explanation:
Similar questions