Math, asked by rubalchdhr, 10 months ago

Find the value of 9 sec2 A - 9 tan2 A.

Answers

Answered by sriram979

13

=9(sec 2a-tan2a)

9(1/cos 2a-sin2a/cos2a

9(1-sin2a/cos2a)

9(cos*2(a)+sin*2(a)-sin2a/cos 2a)

9(cosa-sina)*2/cos 2a

Answered by payalchaudhary885

20

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