find the value of 9 upon 64 power minus 1 upon 3 please solve this question immediately
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How to solve for exponents
- xn=y. Take the log of both sides:
- logxn=logy. By identity we get:
- n⋅logx=logy. Dividing both sides by log x: n=logylogx. Find the exponent of a number.
- 3n=81. Take the log of both sides:
- log3n=log81. By identity we get:
- n⋅log3=log81. Dividing both sides by log 3: n=log81log3.
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