Question

Find the value of 999 whole square by using algebraic identity (a-b) whole square = a square+b square-2ab
$999 {}^2$
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Answer 1

Answer:

998001

Step-by-step explanation:

$999 = (1000 - 1) \\ {999}^{2} = {(1000 - 1)}^{2} \\ {(1000 - 1)}^{2} = {1000}^{2} - 2(1000)(1) + {1}^{2} \\ = 1000000 - 2000 + 1 \\ = 998000 + 1 \\ = 998001$

hope you get your answer

Answer 2

Answer:

999=(1000−1)

999

2

=(1000−1)

2

(1000−1)

2

=1000

2

−2(1000)(1)+1

2

=1000000−2000+1

=998000+1

=998001