Question

Find the value of 9Sec2A-9Tan2A.

Answer 1

Answer:

We have,  9sec2A−9tan2A

Let  r=9sec2A−9tan2A

r=9(sec2A−tan2A)

We know that

sec2A−tan2A=1

Therefore,

r=9×1=9

Hence, this is the answer

Answer 2

Answer:

9

Step-by-step explanation:

Given,

9 sec² A - 9 tan²A

Using identity sec²A = 1 + tan²A.

= 9 (1 + tan²A) - 9 tan²A    

= 9 + 9 tan²A - 9 tan²A

Subtract both terms to obtain:

= 9