Find the value of 9Sec2A-9Tan2A.
Answers
Answered by
6
Answer:
We have, 9sec2A−9tan2A
Let r=9sec2A−9tan2A
r=9(sec2A−tan2A)
We know that
sec2A−tan2A=1
Therefore,
r=9×1=9
Hence, this is the answer
Answered by
4
Answer:
9
Step-by-step explanation:
Given,
9 sec² A - 9 tan²A
Using identity sec²A = 1 + tan²A.
= 9 (1 + tan²A) - 9 tan²A
= 9 + 9 tan²A - 9 tan²A
Subtract both terms to obtain:
= 9
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