Math, asked by amruthamurugan18, 2 months ago

Find the value of 9tan2A+9.
Answer plss...​
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Answers

Answered by jiyashah2901
0

We have, 9sec

2

A−9tan

2

A

Let r=9sec

2

A−9tan

2

A

r=9(sec

2

A−tan

2

A)

We know that

sec

2

A−tan

2

A=1

Therefore,

r=9×1=9

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