find the value of 9x square + 4y square if xy = 6 and 3x + 2y = 12
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Answer:
Explanation:
We need to find the value of 9x^2+4y^2.
Given that, xy=6 and 3x+2y=12.
Now, 9x^2+4y^2
= (3x)^2+(2y)^2
= (3x+2y)^2+2×3x×2y. { APPLYING (a+b)^2-2ab=a^2+b^2}
= (12)^2+12xy
= 144+12×6
=12(12+6)
= 12×18
=216
Hence,9x^2+4y^2= 216.
HOPE THIS WILL HELP YOU.
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