Question

find the value of ( a +1) ( 1 - a) (1- a + a^2) ( 1+ a + a^2) (1 + a^3 × a^3)​

Answer 1

$\fontsize{18}{10}{\textup{\textbf{The required value is (1-a^12)}}}$$\fontsize{18}{10}{\textup{\textbf{The required value is 1-a^{12} }}}$$\fontsize{18}{10}{\textup{\textbf{The required value is 1-a{pow(12)} }}}$

Step-by-step explanation:

( a +1) ( 1 - a) (1- a + a^2) ( 1+ a + a^2) (1 + a^3 × a^3)​

=[( a +1)  (1- a + a^2)] [( 1 - a)( 1+ a + a^2) ](1 + a^3 × a^3)

=(1+a^3)(1-a^3)(1+a^6)

=[(1+a^3)(1-a^3)](1+a^6)

=(1-a^6)(1+a^6)

=1-a^12