Question

Find the value of (a+1)(a-1)(a^2+1).​

Answer 1

Answer:

Answer is 0

Step-by-step explanation:

Let,

(a+1)(a-1)(a^2+1)=0

(a^2-1)(a^2+1)=0

(a^2)^2- 1=0

(a^2)^2=1

a^2=√1

a^2=1

a=√1

a=1.............(1)

putting the value of a

(1+1)(1-1)(1^2+1)

2×0×2

0