Question

find the value of ( a+1)(a-1)(a power2 +1)​

Answer 1

Answer:

the value of (a - 1/a)^2 = 4.

Explanation:

Given:x=

2

+1

= \ \textgreater \ \frac{1}{a} = \frac{1}{ \sqrt{2} + 1 } * \frac{ \sqrt{2} - 1 }{ \sqrt{2} - 1 }= \textgreater

a

1

=

2

+1

1

∗

2

−1

2

−1

= \ \textgreater \ \frac{ \sqrt{2} - 1 }{(2)^2 - ( \sqrt{1} )^2}= \textgreater

(2)

2

−(

1

)

2

2

−1

= \ \textgreater \ \sqrt{2} - 1= \textgreater

2

−1

Now,

= \ \textgreater \ a - \frac{1}{a} = \sqrt{2} + 1 - ( \sqrt{2} - 1)= \textgreater a−

a

1

=

2

+1−(

2

−1)

= \ \textgreater \ 2= \textgreater 2

Hence:

= > (a - 1/a)^2 = (2)^2

= 4.

Therefore the value of (a - 1/a)^2 = 4.

Hope this helps!

Answer 2

answer:

a^4-1 is the right answer

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