Question

Find the value of (a+1)(a-1)(a²+1).​

Answer 1

$\huge\underline\mathbb\color{red}{ANSWER}$

Identity used :- (a+b)(a-b) = a²-b²

$(a + 1)(a -1)( {a}^{2} + 1)$

$= ( {a}^{2} - {1}^{2} )( {a}^{2} + 1)$

$= ( {a}^{2} - 1)( {a}^{2} + 1)$

$= { ({a}^{2}) }^{2} - {1}^{2}$

$= {a}^{4 } - 1$

Answer 2

Answer:(a^4 - 1 )

Step-by-step explanation:

We have been given the expression:-

(a+1)(a-1)(a²+1)

Using the identity a² - b² =(a+b)(a-b)  :-