find the value of
a 115
b 116
c 114
d 144
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abhishek3786kupa3aco:
116
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Answered by
3
Hello here is your answer.
given : x+y =12,xy=14
so , by using (a+b)^2=a^2 +b^2+2ab
(x+y)^2 =x^2+y^2+2xy
144=x^2+y^2 +28
144-28=x^2 +y^2
x^2+y^2 = 116 . HOPE YOU LIKE IT.
given : x+y =12,xy=14
so , by using (a+b)^2=a^2 +b^2+2ab
(x+y)^2 =x^2+y^2+2xy
144=x^2+y^2 +28
144-28=x^2 +y^2
x^2+y^2 = 116 . HOPE YOU LIKE IT.
pls mark it as brainliest
Answered by
2
(x+y)^2 = x^2 + y^2 + 2xy
(12)^2 = x^2 + y^2 + 2×14
144 = x^2 + y^2 + 28
144 - 28 = x^2 + y^2
116 = x^2 + y ^2
.
.
.
hope it will help.....
(12)^2 = x^2 + y^2 + 2×14
144 = x^2 + y^2 + 28
144 - 28 = x^2 + y^2
116 = x^2 + y ^2
.
.
.
hope it will help.....
hii mehak
please mark as brainliest......please
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