Math, asked by tmmmmm, 10 months ago

Find the value of a^2+4b^2+9c^2 if a+2b+3c=6 and 2ab+6bc+3ac=11 pls answer

Answers

Answered by itzANCY

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Answered by TakenName

The square of expression with three terms has six terms.

Three of them comprises square, the rest comprises multiplication of 2 and each other.

→ $(a+2b+3c)^2=a^2+4b^2+9c^2+4ab+12bc+6ca$

Now you can see what values you need to put into.

→ $a+2b+3c=6$

→ $4ab+12bc+6ca=22$

Since expressions are denoted by =, you can use basics of equality to find out the value.

I won't find the value for you. I want to help somebody understand the question.

One can memorize all the formulas, but they won't be able to solve any questions. I hope it helps.

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