Question

find the value of a^2+b^2 when: a+b=4, ab=3

Answer 1

a + b is equal to 4 and a into b is equal to 3 Hence a + b whole square is equal to 16 that is 4 squared. and there is a identity a plus b whole square is equal to a square + b square + 2 AB. we have the value of a b that is equal to 3 and 2 times a b is equal to 6 there for a square + b square is equal to a + b whole square - 2 X A B is equal to 16 - 6 that is equal to 10

Answer 2

$\textbf{ \large { \underline{ Hello Mate! }}}$

${a}^{2} + {b}^{2} = ? \\ a + b = 4 \\ ab = 3$

On squaring both sides we get

${(a + b)}^{2} = {4}^{2} \\ {a}^{2} + {b}^{2} + 2ab = 16 \\ {a}^{2} + {b}^{2} = 16 - 2(3) \\ {a}^{2} + {b}^{2} = 10$

$\boxed{ Hence\:answer\:is\:10 }$

Have great future ahead!