Math, asked by zohair53, 1 year ago

find the value of a^2 + b^2: when a+b = -8 and a-b = -6

Answers

Answered by Swastikagarwal
1
solve the two equations to find value of a and b

2a= -14
a=-7
b=-1

required value (-7)^2+(-1)^2
49+1
50 is the answer

Swastikagarwal: please mark brainliest
zohair53: it is the most helpful i will mark it brainliest
Swastikagarwal: thanks
Answered by Anonymous
1
 \ll \ll\bold{ \huge{ \color{red}{ \fbox{ANSWER}}}} \lll \ll \ll



\ll \ll\bold{ \huge{ \color{green}{ \fbox{DHANYAVAAD}}}} \lll \ll \ll



\ll \ll\bold{ \huge{ \color{tomato}{ \fbox{BE BRAINLY}}}} \lll \ll \ll



\ll \ll\bold{ \huge{ \color{gold}{ \fbox{YADUVANSHI \: KING}}}} \lll \ll \ll




Given:- (a+b)=-8

(a-b)=-6

Solve Equation (1) and (2)

a+b+a-b=-8+(-6)

2a=-14

a=-14/2

a=7

or

b=-1

Again

a²+b²

(-7)²+(-1)²

49+1

=50

Swastikagarwal: its wrong... how can addition of two squared nunbers be negative....
Swastikagarwal: oh sorry .. its anyways wrong.
Anonymous: Sorry...
Anonymous: again check
Similar questions