*Find the value of (a + 2b − c)(2b + c − a)(c + a − b), if a, b, c, are in an A.P.*
1️⃣ (abc)/2
2️⃣ abc
3️⃣ 2abc
4️⃣ 4abc
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Explanation.
→ a, b, c are in Ap.
→ Therefore,
→ First term = a
→ common difference = d = b - a = c - b
→ 2b = a + c → conditions of an Ap.
→ ( a + 2b - c) ( 2b + c - a) ( c + a - b)
→ put the condition in this equation.
→ ( a + a + c - c) ( a + c + c - a) ( 2b - b )
→ ( 2a ) ( 2c ) ( b)
→ 4abc
→ Therefore,
→ Option [ D ] is correct answer.
→ More information.
→ Nth term of an Ap.
→ An = a + ( n - 1 ) d
→ Sum of Nth term of an Ap.
→ Sn = n/2 [ 2a + ( n - 1 ) d ]
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