Question

Find the value of:
a) (3^0 + 6^-1)*2^2

Answer 1

Answer:

4.66666667

but in the shortcut their answer is 4.67

Answer 2

Answer:

 The value of $(3^{0} +6^{-1 } ) (2^{2})$  = $\frac{ 14}{ 3}$ = 4.666...

Step-by-step explanation:

Given problem =  $(3^{0} + 6^{-1} )$ × ($2^{2}$)  

• The value of  $n^{0}$ is always 1  where n is any number

 for example  $8^{2}$ = 1  $1^{2} = 1$,  $6^{0}$ = 1 like that $3^{0} = 1$

• The term  $6^{-1}$ can be written as  $\frac{1}{6}$      

   ∴  given problem  =  $(3^{0} + 6^{-1} )$ × $(2^{2} )$

                                  =   $[1+ \frac{1}{6} ] 4$

                                  = $(\frac{7}{6} )( 4)$     [ (6×1)+ 1 = 7]

                                  = $\frac{ 28}{ 6}$ = $\frac{ 14}{3}$ = 4.666....