Question

Find the value of


a-³ X b-² X c-³ x d⁴ / a⁴xbxc-³xd⁴​

Answer 1

(x−a)

3

+(x−b)

3

+(x−c)

3

−3(x−a)(x−b)(x−c) and a+b+c=3x

We know that a

3

+b

3

+c

3

−3abc=(a+b+c)(a

2

+b

2

+c

2

−ab−ac−bc)

If (a+b+c)=0, then.a

3

+b

3

+c

3

=3abc

Here,a=x−a

b=x−b

c=x−c and a+b+c=x−a+x−b+x−c=3x−(a+b+c)=3x−3x=0

Thus,(x−a)

3

+(x−b)

3

+(x−c)

3

−3(x−a)(x−b)(x−c)

=0

Answer 2

Answer:

a^-7×b^-3

Explanation:

so when you divide these eqns using there powers

=a^-3-4×b^-2-1×c^-3+3×d^4-4

[this "^" means to the power of]

=a^-7×b^-3×c^0×d^0

=a^-7×b^-3