find the value of a
√32+√48 upon √8+√12
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Answer:
√2*2*2*2*2+√2*2*2*2*3/√2*2*2+√2*2*3
=4√2+4√3/2√2+2√3
=4(√2+√3)/2(√2+√3)
=4/2=2
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