Find the value of a
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Given
x2-6x+a=0
a, b are the zeroes of the polynomial
= a +3=6 --(i)
aB = a ---- (ii)
Given
3a +2B = 20 --- (iii)
Solving i and iii we get
a=8
B=-2
Substitution these values in ii we get
(8)(-2) = a
a= -16
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