find the value of a^6-*b+1)^3 when a=1/2,b= -3/4
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Cubing both the sides.
x3 + x 3 1 +3(x+ x 1 )=3 3
⇒x 3 + x 3 1 +3( 3 )=33
x 3 + x 3 1 =0⇒ x 3 x 6 +1 =0
x 6+ 1 = 0
Now, x 18 +x 12 +x 6 +1
⇒x 12 (x 6 +1)+(x 6 +1)
From (1) x 12 (0) + (0) = 0
Step-by-step explanation:
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