Question

Find the value of a&b,if (3+√2)/(3-√2)=a+b√2​

Answer 1

Answer:

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Answer 2

$\huge\underline\mathfrak{Answer:}$

$\huge{\boxed{\boxed{a=11/7}}}$

$\huge{\boxed{\boxed{b=6/7}}}$

$\huge\underline\mathfrak{Explanation:}$

3+√2/ 3-√2 = (3+√2)/(3-√2) * (3+√2)/(3+√2)

= (3+√2)² / (3)²-(√2)²

= 9+2+2(3)(√2) / 9-2

= 11+6√2 / 7

= 11/7 + 6/7 √2

It is given that :

3+√2 / 3-√2 = a+b√2

=> 11/7 + 6/7 √2 = a+b√2

So, by solving this eq we will get the value of a and b .