find the value of a and b
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(5+3√3)÷(7+4√3)=a+b√3
after rationalising we get,
[(5+3√3)(7-4√3)] ÷ [7²-(4√3)²]
=(35-20√3+21√3-36) ÷ (49-48)
= -1+√3
comparing it with a+b√3
a= -1 , b= 1
hope it helped
after rationalising we get,
[(5+3√3)(7-4√3)] ÷ [7²-(4√3)²]
=(35-20√3+21√3-36) ÷ (49-48)
= -1+√3
comparing it with a+b√3
a= -1 , b= 1
hope it helped
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