Question

Find the value of a and b 5+2√3 upon 7+4√3 =a +b √3​

Answer 1

I hope it was helpful

kindly make it the Brainliest answer

Thank you for asking!

Answer 2

$\huge \bf \underline \red{Answer}$

$\bf{ \boxed{ \underline{ \green{ \tt{a = 11, \: b = 6 \: }}}}}$

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$\sf \underline \blue{Given}$

Find the value of a and b 5+2√3 upon 7+4√3 =a +b √3

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$\sf \underline{step \: by \: step \: explanation}$

LHS

$\bf \red{ \frac{5 + 2 \sqrt{3} }{7 + 4 \sqrt{3}}}$

Now we have to multiply to numerator and denominator by 7+4√3 we get,

$\bf \red{⟹ = \frac{(5 + 2 \sqrt{3})(7 - 4 \sqrt{3}) }{(7 + 4 \sqrt{3})(7 - 4 \sqrt{3})} }$

$\bf \blue{⟹ = \frac{35 - 20 \sqrt{3 + 14 \sqrt{3} - 24 } }{ {7}^{2} - (4 \sqrt{3} {}^{2}) }}$

$\bf \green{⟹ algebraic \: formula}$

$\bf{ \boxed{ \underline{ \red{ \tt{(x + y)(x - y) = {x}^{2} - {y}^{2} \: }}}}}$

we get,

$\bf \orange{⟹ = \frac{11 - 6 \sqrt{3} }{49 - 48}}$

$\bf \pink{⟹ = 11 - 6 \sqrt{3} \: is \: eq(1)}$

Given RHS

$\bf{a - b \sqrt{3} \: is \: eq(2)}$

now compare both we get

$\bold \red{a = 11}$

$\bold \blue{b = 6}$

I hope it's help uh