Question

Find the value of a and b :
(7+3√5÷3+√5)-(7-3√5÷3-√5)=a+√5b

Answer 1

(7+3√5)÷(3+√5) - (7-3√5)÷(3-√5) = a+b√5
=> (3-√5)(7+3√5) - (3+√5)(7-3√5)÷(3+√5)(3-√5) = a+b√5
=> 21+9√5 - 7√5 -15 - 21 - +9√5 -7√5 + 15 ÷ (4) = a+b√5
=> 4√5 ÷ 4 = a+b√5
=> a+b√5 = √5
=> a = 0
b = 1