Question

find the value of a. and. b​

Answer 1

Answer:

$\frac{ \sqrt{3} - 1}{ \sqrt{3} + 1 } = a - b \sqrt{3} \\ \\ \frac{ \sqrt{3} - 1}{ \sqrt{3} + 1 } \times \frac{ \sqrt{3} - 1}{ \sqrt{3} - 1 } \\ \\ \frac{( \sqrt{3} - 1) {}^{2} }{ (\sqrt{3}) {}^{2} - (1) {}^{2} } \\ \\ \frac{3 + 1 - 2 \sqrt{3} }{3 - 1} \: \:\: \: [(a-b)^{2}=a^{2}+b^{2}-2ab] \\ \\ \frac{4 - 2 \sqrt{3} }{2} \\ \\ \frac{2(2 - \sqrt{3}) }{2} \\ \\ \bf = 2 - \sqrt{3}$

On comparing 2 - √3 by a - b√3.

a = 2 and b = 1.

Answer 2

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