find the value of a and b......
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solve it u will get u r answer
neha7254:
if have to solve then why I asked this
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Sum of zeros = -(-3)/1
→a+b+a-b+a = 3
→3a = 3
→a = 1
Now , product of zeros = -(1)/1=-1
→ (a-b)(a+b)(a )= -1
→(a^2 -b^2)×1 = -1
→(1)^2 -b^2 = -1
→-b^2 = -2
→b^2= 2
→b =√2 or -√2 ❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤Follow me
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