find the value of A and B. AB-B7=45
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Answer:
a³ — b³ = (a − b)(a² + ab + b²)
3
a³ — b³ = (a - b)(a² - 2ab + b² + 2ab + -
ab)
a³ – b³ = (a − b)[(a−b)² + 3ab] -
a³ - b³ = 4× (4² +3× 45) = 4 × (16 +
135) 4 x 151 = 604
hope it's helpful for you
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