Math, asked by kashishkamboj8842, 9 months ago

find the value of 'a'and 'b'
answer is a= -4/3 and b= 11/3 please give correst answer​

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Answered by ambarkumar1
1

 \frac{ \sqrt{7}  - 2}{ \sqrt{7} + 2 } \times   \frac{\sqrt{7}  -  2}{\sqrt{7}  -  2}  = a \sqrt{7}  + b

 \frac{( \sqrt{7} - 2) {}^{2}  }{( \sqrt{7}) {}^{2}  - 2 {}^{2}  }  = a \sqrt{7}  + b

 \frac{7 + 4 - 4 \sqrt{7} }{7 - 4}  = a \sqrt{7}  + b

 \frac{11 - 4 \sqrt{7} }{3}  = a \sqrt{7}  + b

 \frac{ - 4 \sqrt{7} }{3}  +  \frac{11}{3}  = a \sqrt{7}  + b

On comparison

 <strong> </strong><strong>a = – 4/3</strong>

and

<strong> </strong><strong>b = 11/</strong><strong>3</strong>

Please mark me great if you understood the solution

Answered by nikhilrohilla1234567
1

answer is a=-4/3 and b=11/3

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