Question

Find the value of a and b ...
Any easy method ...​

Answer 1

Answer:

If a,b are the roots of an eqn,

then (x-a)(x-b) = 0 be that quadratic equation.

 If x = 2/3, x = -3 are the two roots, then the eqn will be

     (x-2/3)(x-(-3))=0

 ⇒ (x-2/3)(x+3) = 0

 ⇒ x²-(2/3)x+3x-2 = 0

 ⇒ 3x²-2x+9x-6 = 0

 ⇒ 3x²+7x-6 = 0 is the required eqn.

Compare the eqn with ax²+7x+b = 0

Therefore, a = 3, b = (-6)

Hope it helps! ! !