find the value of a and b BA×B3=
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Basics of Decimals
In the product BA × B3 = 57...
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Asked on December 26, 2019 byHarmanjot Gore
In the product BA×B3=57A, what are the respective positional values of B and A?
A
6, 7
B
5, 2
C
7, 4
D
2, 5
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ANSWER
BA×B3=57A
as B is in 10′s place
⇒(10×B+A)×(10B+3)=(57×10)+A
⇒100B2+10(A×B)+30B+3A=570+A
⇒100B2+10(A×B)+30B+2A=570
⇒2A=570−100B2−10(A×B)−30B
⇒10/2A as 10 divides RHS
⇒A=5
or A=0
for A=0, 100B2+30B=570
⇒10B2+3B=50+7
no B satisfies this as
3B=7
for A=5,100B2+80B+10=
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