find the value of a and b for which equation 2x+3y=7, a (x+y) minus b (x minus y) =(3a+b) has many solution
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2x+3y = 7
a(x+y)+b(x-y) = (3a+b)
x(a+b)+y(a-b) = (3a+b)
for infinitely many solution,
2÷(a+b) = 3÷(a-b) = 7÷(3a+b)
2a-2b = 3a+3b
a+5b = 0
a = -5b
a(x+y)+b(x-y) = (3a+b)
x(a+b)+y(a-b) = (3a+b)
for infinitely many solution,
2÷(a+b) = 3÷(a-b) = 7÷(3a+b)
2a-2b = 3a+3b
a+5b = 0
a = -5b
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