Question

Find the value of a and B for which the following
pair of linear equations has infinite number of
solutions : 2x + 3y = 7;2a x + (a + b) y = 28 (1)​

Answer 1

Answer:

2x+3y=7

2x+3y-7=0

a1x+b1y+c1=0

on comparing

A1=2,B1=3,C1= -7

NOW

2ax+(a+b)y=28(1)

2ax+(a+b)y-28=0

A2X+B2Y+C2=0

on comparing

A2=2a , B2= a+b , C2= -28

now

A.T.Q

A1/A2=B1/B2=C1/C2

2/2a=3/a+b=-7/-28

1/a=3/a+b=1/4

now

1/a=1/4 3/a+b=1/4

after cross multiply. after cross multiply

a=4 12=a+b

now

12=a+b

12=4+b

b=8

Step-by-step explanation:

bhoot aasan solution h