Question

find the value of a and b for which the following system of linear equation has infinite number of solution 2x-3y=0 ; (a+b)x-(a+b-3)y=4a+b​

Answer 1

Answer:

a1/a2=b1/b2=c1/c2

2/(a+b)=-3/(-a-b+3)=7/4a+b

2/a+b=7/4a+b

8a+2b=7a+7b

1a-5b=0.....1

-3/-a-b+3=7/4a+b

-12a-3b=-7a-7b+21

-5a+4b=21....2

1*-5

-5a+25b=0

1-2

-5a+25b=0

-5a+4b=21

21b=-21

b=-1

substituting the value of b in 2

therefore a=5

therefore a and b satisfies equation a+5b=0

5-5=0