find the value of a and b for which the following system of linear equations has infinitely many solutions 3x(a+1)y = 2b-1, 5x+(1-2a)y =3b
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Answer:
3x−(a−1)y=2b−1.................(1)
5x+(1−2a)y=3b.................(2)
Here a1=3,b1=−(a+1) and c1=2b−1
Or a2=5,b2=(1−2a) and c2=3b
Give the system of equations have infinite solutions
a2
a1
=
b2
b1
=
c2
c1
5
3
=
(1−2a)
−(a+1)
⇒−5(a+1)=3(1−2a)
⇒−5a−5=3−6a
⇒a=8
5
3
=
3b
2b−1
⇒9b=10b−5
⇒b=5
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