Question

Find the value of a and b for which the system of equation has infinitely
many solutions: (a – 1)x + (a + 1)y = (3a – 1)and 2x + 3y - 7 = 0.
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Answer 1

Answer:

a = 5

Step-by-step explanation:

For infinite number of solutions,

a1/a2 = b1/b2 = c1/c2

= (a-1)/2 = (a+1)/3 = -(3a-1)/-7

= (a-1)/2 = (a+1)/3 = (3a-1)/7

= (a-1)/2 = (3a-1)/7

= 7(a-1) = 2(3a-1)

=》 7a - 7 = 6a - 2 =》 7a - 6a = 7 - 2

= a = 5

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Answer 2

a-1/3a-1=(a+1)/3=1-3a/-7. ( condition of infinite solution)

now,solve, this equation

3a-3=(3a-1)(a+1)

3a-3=3a^2+3a-a-1

3a^2-a+2=0

solving this ,u will get the required solution