find the value of a and b form the quadratic equation 2x²-5x+7=0
with formula
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Answer:
=−±2−4√2
x=\frac{-{\color{#e8710a}{b}} \pm \sqrt{{\color{#e8710a}{b}}^{2}-4{\color{#c92786}{a}}{\color{#129eaf}{c}}}}{2{\color{#c92786}{a}}}x=2a−b±b2−4ac
Once in standard form, identify a, b and c from the original equation and plug them into the quadratic formula.
22−5+7=0
2x^{2}-5x+7=02x2−5x+7=0
=2
a={\color{#c92786}{2}}a=2
=−5
b={\color{#e8710a}{-5}}b=−5
=7
c={\color{#129eaf}{7}}c=7
=−(−5)±(−5)2−4⋅2⋅7√2⋅2
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