Question

find the value of a and b if (1+i/1-i) ^2​

Answer 1

Answer:

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Answer 2

Answer:

a=-1 & b=0

Step-by-step explanation:

=(1+i/1-i)^2

=1+i^2+2i/1+i^2-2i...........[(a+b)^2=a^2+b^2+2ab]

=1-1+2i/1-1-2i.................[i^2=-1]

=2i/-2i

=-1+0i

Therefore, a=-1 & b=0