find the value of a and b ,if 2/3-2 root 2=a-b root 2
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Answer:
Step-by-step explanation:
Given,
2/3 - 2√2 = a - b √2
⇒ 2- 6√2 / 3 = a - b √2
⇒ 2 -6√2 = 3 (a - b √2)
⇒ 2 - 6√2 = 3a - 3b√2
Comparing same quantities on both sides,we get
⇒ 3a = 2 and - 3b√2 = - 6√2
⇒ a = -2/3 and b = -6√2 / - 3√2
⇒ a = -2/3 and b = 2 ( ∵"-" & √2 are cancelled )
Hence a = -2/3 , b = 2
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