Find the value of a and b if √2+ √3 /
3√2− 2√3
= a + b√6
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(√2+√3)(3√2+2√3)/(3√2-2√3)(3√2+2√3)
=(6+6)/18-12)
12/6=2
=(6+6)/18-12)
12/6=2
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