find the value of a and b if 2-√5/2+3√5=√5a+b
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Answered by
8
the value of a=2 and b=5......i hope its correct...
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therezz:
i think it must be done by rationalizing the denominator
but there is no root in the denominator then what is the use of rationalising?
do you have the answer?
sorry the question i did was wrong
there is 3root 5 in the denominator
wait i will do it once again
okeiii
i got an ans like a=19/-41 and b=-8root/-41
yes
a= 8/41 b=19/-41
Answered by
9
(2-rt5)/(2+3rt5)
(2-rt5)*(2-3rt5)/(2+3rt5)*(2-3rt5)
(4-6rt5-2rt5+15)/(4-45)
(19-8rt5)/-41 = 8rt5-19/41
rt5* a = 8/41
b= -19/41
(2-rt5)*(2-3rt5)/(2+3rt5)*(2-3rt5)
(4-6rt5-2rt5+15)/(4-45)
(19-8rt5)/-41 = 8rt5-19/41
rt5* a = 8/41
b= -19/41
tq
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