find the value of a and b if 3+√2/3-√2-3-√2/3+√2=a+12√2b
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3+ 2 root 3 - root 2- 3 - 2 root 3 + root 2= a + 12× root 2
0=a+12× root b (all positive values will cancel out by negative values).
So, a= 0 and b= 0
0=a+12× root b (all positive values will cancel out by negative values).
So, a= 0 and b= 0
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