Question

find the value of a and b if 3+root 2 ÷3-root2=a+b root 2
plz answer this guys very urgent

Answer 1

3 + √2/3 - √3 = a + b√2

First we will have to rationalize the denominator.

3 + √2/3 - √2 = 3 + √2 (3 + √2)/3 - √2 (3 + √2)

= (3 + √2)^2/(3)^2 - (√2)^2

= (3)^2 + 2*3*√2 + (√2)^2/9 - 2

= 9 + 6√2 + 2/7

= 11 + 6√2/7

Therefore a = 11, b = 6 and then √2

Hope it helps :)

Answer 2

A = 11/7 and B = 6/7

3+root 2/3-root2 *3+root2/3+root2

= (3+ root 2)^2/ (3)^2 - (root2)^2

= 9 + 2 + 6root2/ 9-2

= 11+ 6root2/ 7

now, 11 +6root2 /7= a +b root2

= 11/7 + 6root2/7 = 2 + b root2

use euclid's axiom, that things which coincide with each other are equal to each other, so here

A coincides with 11/7 and B coincides with 6/7 and root 2 by root 2, hence this give you the answer....

just you ur self write all this down in a convineint manner, and u would understand it better....

like this answer if it satisfies you.