find the value of 'a'and 'b' if( 3+root 8/3-root 8) -( 3-root 8/3+root 8) =a +b root 8 b
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Step-by-step explanation:Consider (√a+√b)2
we get it as a+b+2√ab
now, 5 + 2√6 -- if it is a perfect sq, there will be 2 no.s-
such that a+b=5
2√ab=2√6, ab=6 (a=3, b=2)
so, 5 + 2√6 can be written as 3+2+2√3×2
=(√3+√2)2
so SQRT( 5 + 2 SQRT(6)) = √3+√2
similarly, taking SQRT(8-2√15)
a+b=8, ab=15(a=5,b=3)
so SQRT(8-2√15)=(√5-√3)
So √3+√2+√5-√3=√2+√5
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