Find the value of a and b if 3+underroot2/3-underroot2=a+b underroot2
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first proceed from left hand side
and rationalise
we will get 11+6√2
now see right hand
we have a+b√2
so matching our LHS
WE GET a=11,b=6
and rationalise
we will get 11+6√2
now see right hand
we have a+b√2
so matching our LHS
WE GET a=11,b=6
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