Question

find the value of a and b if ​

Answer 1

$\huge\underline\bold{ \pink{ᴀ᭄} \green{N} \blue{S} \purple{W} \red{E} \orange{R}}$

$\frac{3 + \sqrt{2} }{3 - \sqrt{2} } = a + b \sqrt{2}$

$\frac{3 + \sqrt{2} }{3 - \sqrt{2} } \times \frac{3 + \sqrt{2} }{3 + \sqrt{2} } = a + b \sqrt{2}$

$\frac{(3 + \sqrt{2}) {}^{2} }{(3) {}^{2} - (\sqrt{2} ) {}^{2} } = a + b \sqrt{2}$

$\frac{9 + 2 + 6 \sqrt{2} }{3 - 2} = a + b \sqrt{2}$

$\frac{11 + 6 \sqrt{2} }{1} = a + b \sqrt{2}$

$11 + 6 \sqrt{2} = a + b \sqrt{2}$

$on \: comparing \: we \: get$

$\fcolorbox{pink}{aqua}{ \fcolorbox{green}{brown}{ \fcolorbox{blue}{yellow}{a = 11}}}$

$\fcolorbox{green}{red}{\fcolorbox{brown}{pink}{\fcolorbox{blue}{aqua}{b = 6}}}$

$\underbrace\mathcal\red{Please\:mark\:as\:\:Brainliest..............}$

Answer 2

Answer:

hope this helps answer is in the attachment