find the value of a and b if 5+3√2/5-2√2=a+b√2
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nahi aata answer sorry ok
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Solving the LHS,
(5+2√3)/(7+4√3).
Here, since the denominator is not a rational number, we can rationalise it for our ease by multiplying (7–4√3) with the numerator as well as denominator such that we form (a+b)*(a-b) which would be same as a²-b² which is a popular identity.
After multiplying, we would get
(5+2√3)*(7–4√3)/(49–48)=(35–20√3+14√3–24)/1
=11–6√3 or 11+(-6)√3.
Comparing it to RHS , we get a=11 and b=-6.
Thank you.Step-by-step explanation:
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