find the value of A and B if - 5 and - 4 are zeroes of quadratic polynomial aX square + 2 X + b
plx solve this
Answers
Answered by
0
Answer:
ax^2+2x+b
substitute-5 with x
25a-10+b=0
25a+b=10.....1
substitute -4 with x
16a-8+b=0
16a+b=8....2
when we solve 1 and 2 by elimination method
25a+b=10
-16a-b=-8(multiplying with -1 to eliminate b)
--------------
9a =2
--------------
a=2/9
b=40/9
Similar questions